hide save button on successful form completion so we don't get a duplicate submit
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@ -519,7 +519,7 @@ foreach ( $tabs as $name=>$value ) {
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?>
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</ul>
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<div class="clear"></div>
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<form name="contentForm" id="contentForm" method="post" action="<?php echo $_SERVER['PHP_SELF'] ?>" onsubmit="return validateForm( this )">
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<form name="contentForm" id="contentForm" method="post" action="<?php echo $_SERVER['PHP_SELF'] ?>" onsubmit="if(validateForm(this)){$j('#contentButtons').hide();return true;}else{return false;};">
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<input type="hidden" name="view" value="<?php echo $view ?>"/>
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<input type="hidden" name="tab" value="<?php echo $tab ?>"/>
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<input type="hidden" name="action" value="monitor"/>
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@ -1011,7 +1011,7 @@ if ( $monitor->Type() == 'Local' ) {
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</tbody>
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</table>
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<div id="contentButtons">
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<button type="submit" value="Save" onclick="$j('#contentButtons').hide();"<?php echo canEdit('Monitors') ? '' : ' disabled="disabled"' ?>><?php echo translate('Save') ?></button>
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<button type="submit" value="Save"<?php echo canEdit('Monitors') ? '' : ' disabled="disabled"' ?>><?php echo translate('Save') ?></button>
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<button onclick="closeWindow()"><?php echo translate('Cancel') ?></button>
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</div>
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</form>
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